Physics Drafting

[omgabear]

Could someone go over this and tell me if its right. Its the velocity scales for the Kingda Ka.

Height first hill = 138.988m
First drop = 127.00m
Velocity before hitting the first hill = 57.221ms-1

1) (1/2)mv2 + mgh = (1/2)mv2+mgh

Discard the masses due to the fact that the passenger will stay at 60kg throughout the ride.

2) (1/2)v2 + gh = (1/2)v2 + gh

= (1/1) (57.221)2 + 9.8 (0) = (1/2) v2 + 9.8 (139)

= 1637.121 = (1/2) v2 + 1362.2

= 274.921 = (1/2)v2

= 549.842 = v2

3) Square root of 549.842 = v

Therefore passenger has a velocity of 23.448ms-1 at the top of the first hill.


Then going down that hill:

1) (1/2)mv2 + mgh = (1/2)mv2+mgh

Discard masses, due to fact that person will not change weight and stay at 60kg throughout ride.

2) (1/2)v2+gh=(1/2)v2+gh

= (1/2) (23.448)2+ 9.8(127) = (1/2) v2 + 9.8 (0)

= 274.90 + 12.44.6 = 1519.5 = (1/2) v2

= 3039.00 = v2

Square root of 3039.00 = velocity at bottom of hill

Velocity at the bottom of the first hill = 55.127ms-1


+rep for corrections.