PDA

View Full Version : Rearranging Formula



le harry
04-04-2007, 06:29 AM
Hey guys, I need help, I'm going fine in year 10 atm except this is the one thing that doesn't click with me.

like:

Make X the subject of the formula.

Y = 7y x 4x

or whatnot hard to explain without writing

Whats the pattern to work it all out, I just DONT get it!

Thanks.

KnuxIBF
04-04-2007, 10:03 AM
You have to get x on it's own:

eg.

Y = 28xy => Y/28 = xy => Y/28y = x

:]

All you have to do is try and get x on it's own by dividing the other side by everything attached to x...

Hope that helps x]

le harry
04-04-2007, 01:17 PM
Thanks, still kind of confused though. People tell me you have to do whatever you can to get X on it's own. There is no pattern? + rep

France
04-04-2007, 03:24 PM
There is no universal pattern... although the same things apply. You need to get everything else on the other side first (where the x isn't) and then you need to make sure the x is by itself (e.g. if it's being mulitpied by 4, 4x, you need to divide the other side by four)... therefore getting rid of it!

F32
04-04-2007, 09:25 PM
Hey guys, I need help, I'm going fine in year 10 atm except this is the one thing that doesn't click with me.

like:

Make X the subject of the formula.

Y = 7y x 4x

or whatnot hard to explain without writing

Whats the pattern to work it all out, I just DONT get it!

Thanks.
y / x = y[over]x = 7y x 4
/ y = x = 7 x 4[over]y

I think...

Mr.OSH
07-04-2007, 12:05 AM
x must be on its own on its own side of the equation so you must have something that says x=whatever. When you move something that is on one side of the equation to another (to get x on its own) it becomes the opposite so + becomes - and - becomes + and divide becomes x and x becomes divide.

le harry
21-04-2007, 03:14 AM
Thanks! I'm getting the basics of it all through tutoring and help from ya'll thanks!

Papershop
21-04-2007, 03:00 PM
its fairly simple. Whenever you move something over the other side of the "=" sign, it changes to the opposite symbol. ie

7y+6x=x
so
7y=x-6x

Geddit?

So your equation...
Y = 7y x 4x
now this has a times (x) in it, so when u move it over it becomes a divsion

so you get this

1y/7y=4x
so 1/7Y=4x
or 4x=1/7y
now divide the 4 x by 4, to get x. and whatever you do to one side you do to another, so then divide 1/7y by 4

which = 1/28y
so x=1/28y

Lycan
21-04-2007, 03:03 PM
sadly i used to love doing thoose, i found them so easy... just a disturbed boy...

i hate months tho specially now in college with business calculations ... Grr.

Concentric2
22-04-2007, 12:44 AM
just practice. don't be affraid to ask your teacher if you don't get it, and if they're crap at explaining it ask another teacher.
if you get stuck on any post them up and we'll (well, i will anyway) try to help.

le harry
26-04-2007, 11:29 AM
thanks, im getting use to it, we are onto gradient now.. it sucks.

DiscoPat
19-05-2007, 05:39 PM
i suck at maths

Joe.
15-06-2007, 12:12 PM
scrap what i said :(

read the question wrong.

Blinger1
15-06-2007, 12:16 PM
oh i know what you are doing! graphs and stuff, gradient sucks.

if im correct its

m = (y2 - x2) / (y1 - x1)

yeah?

and do BODMAS (Brackets, of devision, multiplication, adition subtraction hehe:)

Want to hide these adverts? Register an account for free!