help with maths!

[Extor]

if g(t²) = -68, find the value(s) of t.


i need all the working yeah?
il rep you :) xx

[jesus]

duz it not tel u wot g is

[Extor]

duz it not tel u wot g is

nope:(

[jesus]

o dats wel homosexual cnt elp ya den soz :[! hug

[Lambda]

It's a function.
You know what t squared equals, so work out the square root.

[,Jess,]

Err is it possible to get a number as an answer? Idk like what level of maths this is..

g(t²) = -68
(/g) t² = -68/G
(√) t = ±√-68/g

± << Thats supposed to be a + and - on top of each other :]
Then / is like fraction
and on the left in brackets is what I did

[Extor]

Err is it possible to get a number as an answer? Idk like what level of maths this is..

g(t²) = -68
(/g) t² = -68/G
(√) t = ±√-68/g

± << Thats supposed to be a + and - on top of each other :]
Then / is like fraction
and on the left in brackets is what I did


its like gcse or whatever u call it, but thanks anyway + rep xx

[fuffie]

ooeer i've done somehting like this not long before i broke up for summer just remember how to do it -.-
try useing mymaths or something that might help ^.^

[Jesus-Egg]

You need to know what the function g(x) is to be able to do the question. Doesn't it say?

[jam666]

if g(t²) = -68, find the value(s) of t.


i need all the working yeah?
il rep you :) xx




dont blame me if im wrong but isnt the answer 34?

because if tx2 = g and g = 68, 68 divided by 2?

[Jesus-Egg]

Hang on, are the brackets there just to show that it's g(t²) and not (gt)²? If so, then ,Jess,'s answer is correct:

g(t²) = -68
t² = -68/g
t = ±√(-68/g)

[Lambda]

Good point. This can actually be different in context, it follows similar notation (f(x), g(x), h(x) or even A(t), usually) to functions which is why we assumed that. Given the picture, Jesus' answer is most likely correct.

[Royksopp]

so T2 x G is -63 then don't you need to find the value of G before you find the value of t?