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Assassinator
04-11-2007, 01:47 PM
Ok lmao so i got this code, but how would i make it so it only shows for userlevel 4?


<?php

if($fetch->ghostmode == "1")
{

echo("Ghostmode[<font color=\"green\">ON</font>]");

}
elseif($fetch->ghostmode == "0")
{

echo("Ghostmode[<font color=\"red\">OFF</font>]");

}

?>

lolwut
04-11-2007, 03:48 PM
Assuming that your userlevel variable is $fetch->level...:



<?php
if($fetch->level <= "4"){
if($fetch->ghostmode == "1") {
echo("Ghostmode[<font color=\"green\">ON</font>]");
}elseif($fetch->ghostmode == "0"){
echo("Ghostmode[<font color=\"red\">OFF</font>]");
}
}
?>

MrCraig
04-11-2007, 03:51 PM
wouldnt that make it so the userlevel has to be less than or equal to 4?



<?php

if($fetch->userlevel == "4"){

if($fetch->ghostmode == "1")
{

echo("Ghostmode[<font color=\"green\">ON</font>]");

}
elseif($fetch->ghostmode == "0")
{

echo("Ghostmode[<font color=\"red\">OFF</font>]");

}

}

?>


I think..

lolwut
04-11-2007, 03:53 PM
No, I did it if userlevel is greater than 4. :rolleyes:

MrCraig
04-11-2007, 04:05 PM
:S

doesnt
<?php
if($fetch->level <= "4"){

indicate less than or equal to?

Blob
04-11-2007, 04:16 PM
== is equal to
!= is not equal to
>= is more than or equal to
<= is less than or equal to
> is more than
< is less than

Assassinator
04-11-2007, 04:20 PM
None of them are coming up lol.

Jae.
09-11-2007, 08:05 AM
<?php
if ($fetch->level != '4'){
die('You do not have the correct user level to enter.');
}
if($fetch->ghostmode == "1"){

echo("Ghostmode[<font color=\"green\">ON</font>]");

}elseif($fetch->ghostmode == "0")
{

echo("Ghostmode[<font color=\"red\">OFF</font>]");

}

?>

Beau
09-11-2007, 11:36 AM
You're trying to use integar statements with strings... Don't quote the numbers.


<?php
if ($fetch->level != 4){
die('You do not have the correct user level to enter.');
}
if($fetch->ghostmode == 1){

echo("Ghostmode[<font color=\"green\">ON</font>]");

}elseif($fetch->ghostmode == 0)
{

echo("Ghostmode[<font color=\"red\">OFF</font>]");

}

?>

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