maths help

[benn!]

how do you do this question? ;s i'm well confused lol

it's probably pretty easy i've just missed it, it's a 3 mark question on a non-calc. paper.

http://i32.tinypic.com/1zb9wmh.png
http://i32.tinypic.com/1zb9wmh.png

edit: do you work out area of triangle, coz there is a right angle so other two are 45deg. then times it by 4 for the square area?

[myke]

The way I've done it is:
Half of the diagonal = One side of the right L'd triangle.
So half of the diagonal = 4.
So do pythagorus, 4 squared and 4 squared = 32. Square root of 32 = 5.7 to the nearest tenth. http://www.worsleyschool.net/science/files/squareroot/eg1aa.gif
Is the real answer for it.
Then do 5.7 x 5.7 which will give you the area.

Probably wrong, but good luck

[benn!]

why do you use pythagoras though? i don't get that bit lol

　　　　| \
　　　　|　 \
4cm　　|　　\　　x
　　　　|　　　\
　　　　|　　 　\
　　　　　3cm

or whatever, thats pythagoras?

[myke]

Turn the square so it's a diamond and you'll see the right angled triangles.

http://i31.tinypic.com/9ibxqf.png
http://i31.tinypic.com/9ibxqf.png

Pythagorus said i any right angled triangle. The sum on the hypotenuse is equal to the sum of the squares of the other two sides.

[Soka]

the two inside lengths of each triangle are 4 i'm assuming

using pythag, c^2 = a^2 + b^2

c = square root of 32 - this is also length of square.

area of square = length squared

length = square root of 32

root32 X root 32 = 32 cm squared so answer is 32 square cm

[benn!]

oh yeah i just realised why you use pythagoras lol

sorry, and thanks :D!