Quick Variable Question

[Colin-Roberts]

How would i make it so it inserts the data into the text file that matches $category.

like so:
$read = fopen("$category.txt", "r");
$contents = fread($read, filesize('$category.txt'));

but clearly proper way..

[Joe!]

I think putting {} around the variable should make it work. so like fopen("{$category}.txt", "r") if that doesn't work, try fopen("".$category.".txt", "r")

[Colin-Roberts]

Warning: filesize() [function.filesize (http://www.mini-roberts.com/tim/function.filesize)]: stat failed for ".$category.".txt in /home/chong08/public_html/mini-roberts.com/tim/adddef.php on line 53

Warning: fread() [function.fread (http://www.mini-roberts.com/tim/function.fread)]: Length parameter must be greater than 0 in /home/chong08/public_html/mini-roberts.com/tim/adddef.php on line 53

[Joe!]

You changed the second line as well yeah?

[Colin-Roberts]

yep, changed all 3 of them

[Invent]

How would i make it so it inserts the data into the text file that matches $category.

like so:
$read = fopen("$category.txt", "r");
$contents = fread($read, filesize('$category.txt'));

but clearly proper way..



$read = fopen( $category . '.txt', 'r' );
$contents = fread( $read, filesize( $category . '.txt' ) );

[Joe!]

well
$read = fopen("".$category.".txt", "r");
$contents = fread($read, filesize("".$category.".txt")); looks like it should work to me.. i'm not really sure how else to do it..

[Colin-Roberts]

i'm just going do it all in mysql instead..

[Joe!]

i'm just going do it all in mysql instead..
Much easier, nice choice.