Image upload [Archive]

Thomas

19-11-2011, 03:33 PM

I've only tired php once and i gave up but i really want to learn it so i'm starting off with a project involving php.

Image upload website.

I got this code off w3schools but it doesn't work, I know i shouldn't just copy and paste the code but if someone would explain/tell me the problem with the code it would help.

Remember i know nothing about php so don't say 'you need to do this' because i won't know how to do that.

REP+ for replies :)

Here is the code:

Index.html:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN""http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html>

<head>
<title> Scrni.com - Image sharing made simple.</title>
</head>

<body>
<form action="upload_image.php" method="POST" enctpye="multipart/form-data">
<input type="file" name="browse" id="file"/><br/>
<input type="file" name="browse" id="file"/><br/>
<input type="file" name="browse" id="file"/><br/>
<input type="file" name="browse" id="file"/><br/>
<input type="file" name="browse" id="file"/><br/>
<input type="submit" name="submit" value="Upload"/>

</body>

</html>

upload_image.php:

<?php
if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/pjpeg")
|| ($_FILES["file"]["type"] == "image/png"))
&& ($_FILES["file"]["size"] < 10000000))
{
if ($_FILES["file"]["error"] > 0)
{
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
}
else
{
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES["file"]["name"] . " already exists. ";
}
else
{
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
}
}
}
else
{
echo "Invalid file";
}
?>