Nisus
07-09-2005, 08:58 AM
Titrahon results-
expt 1
initial bunette reading = 2.0 cm3
final “ “ = 30.6 cm3
volume of acid used = 27.4cm3
expt 2
initial bunette reading = 0.5 cm3
final “ “ = 28.5 cm3
volumeof acid used = 28.00 cm3
expt 3
25cm3 of ammonium, no idicater used
Volume of acid added = 27.9cm3
Calculation –
Equation for the reaction is
H2so4 + 2nh3 à (nh4)2so4
Theoretical yield-
Relahave atomic masses
H=1
S=32
O=16
N=14
Molecular mass of sulphuric acid h2so4
= (2x1) + 32 + (4x16)
= 2 + 32 + 64
= 98g
Molecular mass of ammonia nh3
= 14 + (3x1)
= 17g
Molecular mass of ammonium sulphate (nh4)2 so4
= (2x14) + (8x1) + 32 + (4x16)
= 28 + 8 + 32 + 64
= 132g
Amount of sulphuric acid used
- 98g of h2so4 in 1000cm3 of water as it is 1 molar strength
- But u will use a smaller volume vcm3 in the titration
- So the actual mass of h2so4 will be less than 98g, let this be m grams
So the amount theoretically used is:
M=98xv
1000
=98x27.9
1000
The theoretical yield is 2.73g
Percentage yield –
Percentage yield = actual yield x 100 = %
Theoretical yield
= 1.451 x 100
3.68
= 38.3 %
expt 1
initial bunette reading = 2.0 cm3
final “ “ = 30.6 cm3
volume of acid used = 27.4cm3
expt 2
initial bunette reading = 0.5 cm3
final “ “ = 28.5 cm3
volumeof acid used = 28.00 cm3
expt 3
25cm3 of ammonium, no idicater used
Volume of acid added = 27.9cm3
Calculation –
Equation for the reaction is
H2so4 + 2nh3 à (nh4)2so4
Theoretical yield-
Relahave atomic masses
H=1
S=32
O=16
N=14
Molecular mass of sulphuric acid h2so4
= (2x1) + 32 + (4x16)
= 2 + 32 + 64
= 98g
Molecular mass of ammonia nh3
= 14 + (3x1)
= 17g
Molecular mass of ammonium sulphate (nh4)2 so4
= (2x14) + (8x1) + 32 + (4x16)
= 28 + 8 + 32 + 64
= 132g
Amount of sulphuric acid used
- 98g of h2so4 in 1000cm3 of water as it is 1 molar strength
- But u will use a smaller volume vcm3 in the titration
- So the actual mass of h2so4 will be less than 98g, let this be m grams
So the amount theoretically used is:
M=98xv
1000
=98x27.9
1000
The theoretical yield is 2.73g
Percentage yield –
Percentage yield = actual yield x 100 = %
Theoretical yield
= 1.451 x 100
3.68
= 38.3 %