FUNCTION

*Message Removed*

Edited by Agesilaus (Forum Moderator): Please do not be rude.

Quote:

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Originally Posted by Sangreal

Thats what i got...

PHP Code:

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function replace($string)
{

 $pattern = array("{site_domain}", "{site_name}"); 

 $replacement = array("$site_domain", "$site_name"); 

 str_replace($pattern, $replacement, $string);

 return $string;
} 


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All variables are already defined.... but the function wont work... it physically does doesnt change it to anything. Your all saying the same thing, and im saying if you listen, its not working...

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If $site_domain and $site_name are already defined in the script then you need to global them into the function:

PHP Code:

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function replace($string) {
global $site_domain,$site_name;
.... 


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Quote:

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Originally Posted by Baving

If $site_domain and $site_name are already defined in the script then you need to global them into the function:

PHP Code:

---

function replace($string) {
global $site_domain,$site_name;
.... 


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not always, you could do:

PHP Code:

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class hi
{
var $sitedomain;
var $site_name;
function replace($string)
{
whatever
}
} 


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and then do

PHP Code:

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$function = new hi;
$function->sitedomain = $sitedomain;
$function->site_name = $site_name;
$function->replace("hi"); 


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although yours is easier.

Quote:

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Originally Posted by Baving

If $site_domain and $site_name are already defined in the script then you need to global them into the function:

PHP Code:

---

function replace($string) {
global $site_domain,$site_name;
.... 


---

---

I didn't think you had to global things in unless they were in a class?

Wow, learn something new every day =]

Quote:

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Originally Posted by Dentafrice,

I didn't think you had to global things in unless they were in a class?

Wow, learn something new every day =]

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neither did i, and i just learnt what global did lol.

edit: btw, ive only seen global in a class before and didnt have a clue what it meant, so, ye.

If you do not global outside variables into the function then the newly defined variables within the function will be returned as null.

Example:

PHP Code:

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$site='32';
function something($string) {
$string = $site.$string;
} 


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The value of $site within the function would be blank / null.

Quote:

---

Originally Posted by Baving

If you do not global outside variables into the function then the newly defined variables within the function will be returned as null.

Example:

PHP Code:

---

$site='32';
function something($string) {
$string = $site.$string;
} 


---

The value of $site within the function would be blank / null.

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so if you did global in a class you would be able to use the variables in all of the class' functions?

I believe you need to global it on each function.