xy=27 and logxY + logyX =5/2
find x and y
anyone know the answer?

xy=27 and logxY + logyX =5/2
find x and y
anyone know the answer?
What exactly do you mean by logxY and logyX? What are capital X and Y?
logxY
x at down
u took additional math too?
gosh im bad in logarithm...
Sorry I don't understand your notation. Do you mean by logxY=c that x to the power c equals Y (x^c=Y)?
i duno how to explain
xy=27 and LOGxY + LOGyX =5/2
sorry for double post
Last edited by doraemonkiller; 01-02-2006 at 02:05 PM.
urm im stuck here:
logxY + logyX =5/2
log Y / log X + log X / log Y = 5/2
yah me tooOriginally Posted by Violentine
urm im stuck here:
logxY + logyX =5/2
log Y / log X + log X / log Y = 5/2
XY= 27
how to find X and Y
Last edited by doraemonkiller; 01-02-2006 at 02:14 PM.
ooers...
hrm, i got to this:
log yY / log yX + log xX / log xY = 5/2
1 / log yX + logyX = 5/2
now idk wut to do lorl
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