Write a FizzBuzz program in a language of your choice in under 4 minutes

[Agnostic Bear]

Loop from 1 to 100,

If the number is divisible by 3, it must print fizz.
If the number is divisible by 5, it must print buzz.
If the number is divisible by both 3 and 5 it must print fizzbuzz.

If divisible by neither, neither fizz or buzz should be printed.


Just a small something to waste some time.

[Jamesy]

<?php
    $Count = 1;
    while ($Count < 101) 
    {
        echo $Count;
        
        if ($Count % 3 == 0)
        {
            echo  " fizz";    
        }
        
        if ($Count % 5 == 0)
        {
            echo " buzz";    
        }

        echo "<br />";    

        $Count++;
    }
?>

There are probably nicer ways of doing it I guess.

[Jaiisun]

used turbo delphi:

var
  count : integer;
begin
  count := 1;
  repeat
    if count mod 3 = 0 then write ('fizz');
    if count mod 5 = 0 then write ('buzz');
    writeln;
    count := count + 1;
  until count = 101;
readln;
end.

[Jonster]

Written in Python:

for number in range(1,101):

    if number % 3 == 0:
        if number % 5 == 0:
            print(str(number)+" : fizzbuzz")
        else:
            print(str(number)+" : fizz")

    elif number % 5 == 0:
        if number % 3 == 0:
            print(str(number)+" : fizzbuzz")
        else:
            print(str(number)+" : buzz")
        
    else:
        print(str(number)+" : --")

Which outputs (first 15):

1 : --
2 : --
3 : fizz
4 : --
5 : buzz
6 : fizz
7 : --
8 : --
9 : fizz
10 : buzz
11 : --
12 : fizz
13 : --
14 : --
15 : fizzbuzz

[MattFr]

Actionscript 3, messy but whatever

package  
{
	public class Application
	{
		
		public function Application() 
		{
			for (var i:int = 1; i <= 100; i++)
			{
				trace(i);
				if (i % 3 == 0)
				{
					trace("FIZZ");
				}
				if (i % 5 == 0)
				{
					trace("BUZZ");
				}
				
				trace("--");
			}
		}
		
	}

}

[Agnostic Bear]

<?php
    $Count = 1;
    while ($Count < 101) 
    {
        echo $Count;
        
        if ($Count % 3 == 0)
        {
            echo  " fizz";    
        }
        
        if ($Count % 5 == 0)
        {
            echo " buzz";    
        }

        echo "<br />";    

        $Count++;
    }
?>

There are probably nicer ways of doing it I guess.

Hahaha, I wrote this yesterday before posting the thread, eerily similar:

<?php
for( $i = 1; $i <= 100; $i++ )
{
    echo $i . ' - ';
    if( $i % 3 == 0 ) { echo 'Fizz'; }
    if( $i % 5 == 0 ) { echo 'Buzz'; }
    echo '<br />';
}
?>

[Invent]

Just another way of doing it in PHP

for( $i = 1; $i <= 100; $i++ ) {

    echo $i, ' - ', ( ( $i % 3 === 0 ) ? 'Fizz' : '' ), ( ( $i % 5 === 0 ) ? 'Buzz' : '' ), '<br />';

} 

[Jamesy]

It's getting smaller and smaller haha!

[Hitman]

<?php fizzbuzzgame(1-100, 3, 5.print) ?>

---------- Post added 02-07-2010 at 09:08 PM ----------

I tried yesterday, took me 10 minutes to get down 2 lines of ********. My PHP is not great.

[Hitman]

And there is some big ass silence... mine, of course, was a joke. Anybody else got any other languages they can do this in? Javascript?