PHP to display number of days since given date?

[Flumples]

I have very little PHP knowledge, usually I can find anything out with a google search but can't find this anywhere.

I need to display the number of days since a given date, basically I need a counter that increases by 1 each day.

Any ideas?

[LMS16]

I made this, it basically works abit like facebooks timer (under status' & posts etc..)

Edit it to how you need it

function howLong($timestamp) {
    $diff = time()-$timestamp;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    return "on " . date("jS F, Y", $timestamp);
} 

Enjoy, Lew.

[Flumples]

Thanks! You're gonna have to help me to get it to display on a page though, I really am SUCH a php noob!! I've tried wrapping <?php and ?> tags round it but didn't work, probably doing it all wrong

[HotelUser]

Thanks! You're gonna have to help me to get it to display on a page though, I really am SUCH a php noob!! I've tried wrapping <?php and ?> tags round it but didn't work, probably doing it all wrong

try this:

<?php
function howLong($timestamp) {
    $diff = time()-$timestamp;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    return "on " . date("jS F, Y", $timestamp);
}  

howLong(time());
?>

[Trinity]

I made this, it basically works abit like facebooks timer (under status' & posts etc..)

Edit it to how you need it

function howLong($timestamp) {
    $diff = time()-$timestamp;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    return "on " . date("jS F, Y", $timestamp);
} 

Enjoy, Lew.

That's not what he asked for though, he wants to display the number of days, not seconds/minutes/hours.

try this:

<?php
function howLong($timestamp) {
    $diff = time()-$timestamp;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    return "on " . date("jS F, Y", $timestamp);
}  

howLong(time());
?>

That wouldn't work, it says time() - time().

I'd do this:

function plural($num) {
    if ($num != 1)
        return "s";
}
 
function getRelativeTime($date) {
    $diff = time() - $date;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    if ($diff<7)
        return $diff . " day" . plural($diff) . " ago";
    $diff = round($diff/7);
    if ($diff<4)
        return $diff . " week" . plural($diff) . " ago";
    return "on " . date("F j, Y", strtotime($date));
}

// Unix timestamp for today at 17:21:19, replace this with a timestamp for whenever you want
$stampystamp = 1295803279;

// Display the number of seconds/minutes/hours/days/weeks since the timestamp
echo getRelativeTime($stampystamp); 

Untested and rushed, but should work.

[coolchris322]

 <?php 
function howLong($timestamp) { 
    $diff = time()-$timestamp; 
    if ($diff<60) 
        return $diff . " second" . plural($diff) . " ago"; 
    $diff = round($diff/60); 
    if ($diff<60) 
        return $diff . " minute" . plural($diff) . " ago"; 
    $diff = round($diff/60); 
    if ($diff<24) 
        return $diff . " hour" . plural($diff) . " ago"; 
    $diff = round($diff/24); 
    return "on " . date("jS F, Y", $timestamp); 
}   

howLong("second" + "minutes" + "hours" + "days" + "months" + "years"); //Set a value in each of them. 
?>

[Flumples]

That's not what he asked for though, he wants to display the number of days, not seconds/minutes/hours.



That wouldn't work, it says time() - time().

I'd do this:

function plural($num) {
    if ($num != 1)
        return "s";
}
 
function getRelativeTime($date) {
    $diff = time() - $date;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    if ($diff<7)
        return $diff . " day" . plural($diff) . " ago";
    $diff = round($diff/7);
    if ($diff<4)
        return $diff . " week" . plural($diff) . " ago";
    return "on " . date("F j, Y", strtotime($date));
}

// Unix timestamp for today at 17:21:19, replace this with a timestamp for whenever you want
$stampystamp = 1295803279;

// Display the number of seconds/minutes/hours/days/weeks since the timestamp
echo getRelativeTime($stampystamp); 

Untested and rushed, but should work.

Thanks! Works perfectly

[BoyBetterKnow]

I made this, it basically works abit like facebooks timer (under status' & posts etc..)

Edit it to how you need it

function howLong($timestamp) {
    $diff = time()-$timestamp;
    if ($diff<60)
        return $diff . " second" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<60)
        return $diff . " minute" . plural($diff) . " ago";
    $diff = round($diff/60);
    if ($diff<24)
        return $diff . " hour" . plural($diff) . " ago";
    $diff = round($diff/24);
    return "on " . date("jS F, Y", $timestamp);
} 

Enjoy, Lew.

I'm sure you did code that. http://snipplr.com/view/4912/relative-time/

[Trinity]

I'm sure you did code that. http://snipplr.com/view/4912/relative-time/

That's the one I used, I added the link in the first time I wrote the post, but then I had to go back to include HotelUser's post and forgot to add it in.

[LMS16]

I'm sure you did code that. http://snipplr.com/view/4912/relative-time/

Sorry if you thought I said I made that exact thing, I meant edit

Lew.