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  1. #1
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    Default add math question

    xy=27 and logxY + logyX =5/2
    find x and y

    anyone know the answer?

  2. #2
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    What exactly do you mean by logxY and logyX? What are capital X and Y?

  3. #3
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    logxY
    x at down

  4. #4
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    u took additional math too?
    gosh im bad in logarithm...

  5. #5
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    Sorry I don't understand your notation. Do you mean by logxY=c that x to the power c equals Y (x^c=Y)?

  6. #6
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    i duno how to explain

  7. #7
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    xy=27 and LOGxY + LOGyX =5/2

    sorry for double post
    Last edited by doraemonkiller; 01-02-2006 at 02:05 PM.

  8. #8
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    urm im stuck here:

    logxY + logyX =5/2

    log Y / log X + log X / log Y = 5/2

  9. #9
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    Quote Originally Posted by Violentine
    urm im stuck here:

    logxY + logyX =5/2

    log Y / log X + log X / log Y = 5/2
    yah me too
    XY= 27
    how to find X and Y
    Last edited by doraemonkiller; 01-02-2006 at 02:14 PM.

  10. #10
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    ooers...
    hrm, i got to this:

    log yY / log yX + log xX / log xY = 5/2

    1 / log yX + logyX = 5/2

    now idk wut to do lorl

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