No, that didnt work.
Also, I have the following code, but when the text comes out $username just comes out ast $username.
PHP Code:<?php
// retrieve form data
$username = $_POST['username'];
// check entered value and branch
{
echo 'You have now signed up as $username!';
}
?>
Results 11 to 20 of 24
Thread: PHP Start
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i believe?
PHP Code:<?php
// retrieve form data
$username = $_POST['username'];
// check entered value and branch
{
echo 'You have now signed up as '.$username.'!';
}
?>Last edited by Colin-Roberts; 07-11-2007 at 12:58 PM.
.:.:#14:.:. .:.: Impossible Is Nothing :.:. .:.: 845 Rep:.:.
.:.: Stand up for what is right, even if you stand alone:.:.
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Change the line that says:
if($email = @hotmail.com){
to:
if($email = "@hotmail.com"){
You where missing off the "'s around the email, because you can't put plaintext in if statements if they're not wrapped in "'s.i've been here for over 8 years and i don't know why
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07-11-2007, 04:32 PM #14
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its:
Originally Posted by adamFTW
<?php
// retrieve form data
$username = $_POST['username'];
// check entered value and branch
{
echo "You have now signed up as $username!";
}
?>
my sig ran away,
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07-11-2007, 05:25 PM #15
Try that.PHP Code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
if( $_POST["email"] && !empty($_POST["email"]) )
{
if( preg_match("(\w+@[a-zA-Z_-]+?\.[a-zA-Z]{2,6})", $_POST["email"]) )
{
if( preg_match("(\w+@hotmail+?\.[a-zA-Z]{2,6})", $_POST["email"]) )
{
echo "Sorry we do not allow hotmail emails";
} else
{
echo 'On to the next step....
<form action="username.php" method="post">
Enter desired username:
<br />
<input name="username" size="20" type="text"><br />
<input value="Submit" type="submit">
</form>';
}
} else
{
echo "You entered an invalid email";
}
} else
{
echo "You didnt enter anything for your email";
}
?>
</body>
</html>
And for username:
PHP Code:<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
if( $_POST["username"] )
{
echo 'You have now signed up as ' . $username . '!';
}
?>
</body>
</html>Last edited by Blob; 07-11-2007 at 05:27 PM.
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New error now.
Error: Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /home/habboboa/public_html/wlphp/new/reg.php on line 48
Line 48:
PHP Code:$query = mysql_query("INSERT INTO `system` (`username`, `password`, `age`) VALUES ($username, '$password', '$age'");
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Does it have to do with the ; or ' or does it have to do with the variable itself?
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Try that.PHP Code:
$query = mysql_query("INSERT INTO `system` (`username`, `password`, `age`) VALUES ('$username', '$password', '$age'");
Give us an add like!
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Check the lines before incase you've missed an ; out.
Give us an add like!
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