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  1. #1
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    Default Maths help - Logarithms (+REP)

    I'm stuck on the following question:

    Express log2(x+2) - log2x as a single logarithm.

    Hence solve the equation log2(x+2) - log2x = 3.


    I can do part "a"- log2(x+2) - log2x = log2(x+2)/x

    But how do I do part "b"?

    Its probably so easy haha but anyway, +REP for any help

    Oh and this is for C2 in case there are more advanced methods which you'd otherwise use .
    Last edited by Matthew; 22-10-2012 at 04:47 PM.
    used to fix usertitles n stuff


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  2. #2
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    Okay, so we have:

    log2((x+2)/x) = log((x+2)/x)/log(2) = 3

    Multiply both sides by log(2);

    log((x+2)/x) = 3log(2)

    Take the exponential of both sides;

    (x+2)/x = 8

    Rearrange for x;

    -7x = -2

    x = 2/7

  3. #3
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    Quote Originally Posted by Kardan View Post
    Okay, so we have:

    log2((x+2)/x) = log((x+2)/x)/log(2) = 3

    Multiply both sides by log(2);

    log((x+2)/x) = 3log(2)

    Take the exponential of both sides;

    (x+2)/x = 8

    Rearrange for x;

    -7x = -2

    x = 2/7
    Oh right, I didn't realise that log2 (x) = log (x)/log2.

    Do you know if that is a C2 concept? I've missed one lesson recently so maybe I missed that, although I can't see anything in the text book about it :S

    If it isn't C2, do you know a way that uses a C2 method?
    used to fix usertitles n stuff


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  4. #4
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    Quote Originally Posted by Matts View Post
    Oh right, I didn't realise that log2 (x) = log (x)/log2.

    Do you know if that is a C2 concept? I've missed one lesson recently so maybe I missed that, although I can't see anything in the text book about it :S

    If it isn't C2, do you know a way that uses a C2 method?
    Im sure I told you that in Mod Spam? :S

  5. #5
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    Quote Originally Posted by Matts View Post
    Oh right, I didn't realise that log2 (x) = log (x)/log2.

    Do you know if that is a C2 concept? I've missed one lesson recently so maybe I missed that, although I can't see anything in the text book about it :S

    If it isn't C2, do you know a way that uses a C2 method?
    This video suggests it is a C2 Method

    http://www.youtube.com/watch?v=zKV8Y...ure=plpp_video

    Plus I can't think of any other methods that involve changing the base, and you will have to change the base in order to solve the equation.

  6. #6
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    Quote Originally Posted by Lee View Post
    Im sure I told you that in Mod Spam? :S
    Eh?

    In mod spam you said the following:

    "Ouch" and (along the lines of) "No I can't do it"

    haha

    EDIT:
    Quote Originally Posted by Kardan View Post
    This video suggests it is a C2 Method

    http://www.youtube.com/watch?v=zKV8Y...ure=plpp_video

    Plus I can't think of any other methods that involve changing the base, and you will have to change the base in order to solve the equation.
    Right, thanks for your help
    Last edited by Matthew; 22-10-2012 at 06:41 PM.
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  7. #7
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    Quote Originally Posted by Kardan View Post
    log2((x+2)/x) = log((x+2)/x)/log(2) = 3
    Out of curiosity, why did you bother changing the base? Why not just go:

    log2(x+2 / x) = 3
    x+2 / x = 23

    In one step?

  8. #8
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    Quote Originally Posted by LoveToStack View Post
    Out of curiosity, why did you bother changing the base? Why not just go:

    log2(x+2 / x) = 3
    x+2 / x = 23

    In one step?
    Just to show how to convert bases using the base conversion formula in C2.
    Last edited by Kardan; 23-10-2012 at 10:46 AM.

  9. #9
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    Quote Originally Posted by LoveToStack View Post
    Out of curiosity, why did you bother changing the base? Why not just go:

    log2(x+2 / x) = 3
    x+2 / x = 23

    In one step?
    I'd advise this method. Change of base is a C2 method but you don't need it here.

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