Hang on, are the brackets there just to show that it's g(t²) and not (gt)²? If so, then ,Jess,'s answer is correct:
g(t²) = -68
t² = -68/g
t = ±√(-68/g)
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Thread: help with maths!
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Good point. This can actually be different in context, it follows similar notation (f(x), g(x), h(x) or even A(t), usually) to functions which is why we assumed that. Given the picture, Jesus' answer is most likely correct.
(define (reduce f)((lambda (value) (if (equal? value f) f (reduce value))) (let r ((f f) (g ())) (cond ((not (pair? f)) (if (null? g) f (if (eq? f (car g)) (cadr g) (r f (caddr g))))) ((and (pair? (car f)) (= 2 (length f)) (eq? 'lambda (caar f))) (r (caddar f) (list (cadar f) (r (cadr f) g) g))) ((and (not (null? g)) (= 3 (length f)) (eq? 'lambda (car f))) (cons 'lambda (r (cdr f) (list (cadr f) (delay (cadr f)) g)))) (else (map (lambda (x) (r x g)) f))))))
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so T2 x G is -63 then don't you need to find the value of G before you find the value of t?
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