Calculations (New)

[milky1-2-1]

5928...

13^9

4....
expand: (x+2)(x+4) - simple quadratic equation

[Baving]

x²+4x+2x+8
simplified = x²+6x+8

Expand and Solve
(2x+2)(3x-4)

[milky1-2-1]

x²+4x+2x+8
simplified = x²+6x+8

Expand and Solve
(2x+2)(3x-4)

A) I will expand
B) impossible to solve, becuase there is not an = to so how can i solve X
I will expand , and then you can do the honours of solving with a new maths theory

6x² - 8x + 6 x - 8
= 6x² - 2 x - 8


3 pie divided by 6 pie.. simple

[Baving]

answer = 0.5

find the tn rule for this sequence
4, 8, 14, 22, 32

[milky1-2-1]

answer = 0.5

find the tn rule for this sequence
4, 8, 14, 22, 32

erm
4 8 14 22 32
4 6 8 10
2 2 2

a+b+c = 4 a = 1
3a+b = 4 b = 1
2 a = 2 c= 2

rule: tn = n2 + n + 2

question: (a) find the gradient from the 2 co ordinates ((4,13)(20,77)
(b) from ur answer from part a find the equation of the graph
simple q, for a use the forumla dy over dx

[Baving]

Try this one
Re-write x2 + 6x as a square plus another term.

[milky1-2-1]

Try this one
Re-write x2 + 6x as a square plus another term.

Easy! x2 + 6 x = (x2 + 6x + 9) - 9
= (x + 3)2-9
you still aint solved my previous one

question: (a) find the gradient from the 2 co ordinates ((4,13)(20,77)
(b) from ur answer from part a find the equation of the graph
simple q, for a use the forumla dy over dx

[Baving]

Fine Fine :p
a) DY divided by DX = 64 divided by 16 = 4 = gradient
b) Subsitute gradient in to x in first co-ordinate so 4x = 16, to get to y u take 3 . Equation = 4X-3

Done!

What is 6x8x3x6x9x3 divided by 3?

[milky1-2-1]

Fine Fine :p
a) DY divided by DX = 64 divided by 16 = 4 = gradient
b) Subsitute gradient in to x in first co-ordinate so 4x = 16, to get to y u take 3 . Equation = 4X-3

Done!

What is 6x8x3x6x9x3 divided by 3?

bravo
6x8x3x6x9x3 divide 3 = 7776 - done on paper

square root of 225

[Baving]

15
square root of pie