Factorise Fully :
7f(squared) g (sqaured) - FG
b) 6m(squared) + 13 m + 5
c) 9p(squared) + 18p - 16
d) 12p(squared) - 3
e) 35 - 2q - q Squared
please help
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Factorise Fully :
7f(squared) g (sqaured) - FG
b) 6m(squared) + 13 m + 5
c) 9p(squared) + 18p - 16
d) 12p(squared) - 3
e) 35 - 2q - q Squared
please help
when you say squared
do you mean just the letter squared
or the letter and the number ?
just the letter
nauht there wrong its facroisation
so its like
2 brackets
( )( ) and they should mutilply out to be the same as what i gave you
Do you still need help?
I've been doing this in maths very recently.
1.)
7F2 G2 - FG = FG (7F-G)
2.) 6m2 + 13 m + 5 = M (6M+13+5)
If you need help with the others, just tell me. I don't want to be doing them for a loss cause if you've allready got the answers. :)
number 2 is wrong becuase were looking for 5 and in the brcket it would come out as 5m
bio got any ideas?
no problem when will youhave some spare time to help ?
i'll do no.2 for you because i'm nice
6m(squared) + 13m + 5
=
(2m + 1) (3m + 5)
YOU SHOULD OF RECOGNISED THE QUADRATIC
edit: 3. = (3p+8)(3p-2)
4. = 3(4p-1) i think
5. = (x+5) (x-7)
don't say i never do anything for you.
thanks its allcoming abck to me know youve been some help how cani repay you
have my babies.
Edited by ,Jess, (Forum Moderator): Please do not make pointless posts.
a) 7f2g2 +fg
You need to find the common factor between 7f2g2 and fg, which is fg. So you need to take fg out, and you get:
fg(7fg-1)
b) 6m2+13m+5
This is one of the ones that you need to put in 2 sets of brackets. There's either going to be 6m and m, or 2m and 3m to multiply to give 6m2, but you don't know which. You also know the numbers must multiply to give 5, so they must be 1 and 5. All you can do now is trial and error until you get the right answer, which should be (2m+1)(3m+5)
c) 9p2+18p-16
There's going to be either p and 9p, or 3p and 3p, and the number bit could be either 1 and 16, 2 and 8, or 4 and 4, with one positive and one negative, so again all you can really do is trial and error. You should get the answer (3p+8)(3p-2)
d) 12p2-3
You should notice straight away that 3 is a common factor, so you get 3(4p2-1)
If you look at the bit in the brackets, and imagine it says 4P2+0p-1 you know there's going to be 1 and -1, and to get the 0p, you must have 2p and 2p, therefore the final answer is 3(2p+1)(2p-1)
e) 35-2q-q2
Personally, i prefer to write it as -q2-2q+35. You know that there must be q and -q, and to get -2q, there must be 5 and 7, so you get (q+7)(-q+5), which can also be written as (7+q)(5-q) if you prefer it
Hope that helped :)
No bio, don't tell me i'm wrong as I never put 5m, so get your facts straight. I did this in class the week before half term, and got a's for it therefore I know for sure I am right in my answers. In factorising you need brackets in your answer.
what he meant was that if you were to multiply out your answer of m(6m+13+5), you get 6m2+13m+5m, so your answer cannot be right, as it should be 5, not 5m.Quote:
Originally Posted by Throne Sofa
What type of Factorsing? Factorising is normaly lyke
24p squared - 4p cubed
P4(6p-PPP)
?
where the hell are you gonna use this later in life? schools are bloody ridiculus sometimes
dw lol
i did factorising ages ago
thats quadratics right?
some of them were quadratics