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  1. #11
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    bio got any ideas?

  2. #12
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    Quote Originally Posted by BowTies1 View Post
    bio got any ideas?
    I'll help later, I could do all of them most probaly.

    But i'm really busy right now... & I cba. (;

  3. #13
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    no problem when will youhave some spare time to help ?

  4. #14
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    i'll do no.2 for you because i'm nice

    6m(squared) + 13m + 5

    =

    (2m + 1) (3m + 5)


    YOU SHOULD OF RECOGNISED THE QUADRATIC

    edit: 3. = (3p+8)(3p-2)

    4. = 3(4p-1) i think

    5. = (x+5) (x-7)

    don't say i never do anything for you.
    Last edited by Ramones; 22-10-2007 at 08:31 PM.


  5. #15
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    thanks its allcoming abck to me know youve been some help how cani repay you

  6. #16
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    have my babies.

    Edited by ,Jess, (Forum Moderator): Please do not make pointless posts.
    Last edited by ,Jess,; 23-10-2007 at 12:25 PM.


  7. #17
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    a) 7f2g2 +fg
    You need to find the common factor between 7f2g2 and fg, which is fg. So you need to take fg out, and you get:
    fg(7fg-1)

    b) 6m2+13m+5
    This is one of the ones that you need to put in 2 sets of brackets. There's either going to be 6m and m, or 2m and 3m to multiply to give 6m2, but you don't know which. You also know the numbers must multiply to give 5, so they must be 1 and 5. All you can do now is trial and error until you get the right answer, which should be (2m+1)(3m+5)

    c) 9p2+18p-16
    There's going to be either p and 9p, or 3p and 3p, and the number bit could be either 1 and 16, 2 and 8, or 4 and 4, with one positive and one negative, so again all you can really do is trial and error. You should get the answer (3p+8)(3p-2)

    d) 12p2-3
    You should notice straight away that 3 is a common factor, so you get 3(4p2-1)
    If you look at the bit in the brackets, and imagine it says 4P2+0p-1 you know there's going to be 1 and -1, and to get the 0p, you must have 2p and 2p, therefore the final answer is 3(2p+1)(2p-1)

    e) 35-2q-q2
    Personally, i prefer to write it as -q2-2q+35. You know that there must be q and -q, and to get -2q, there must be 5 and 7, so you get (q+7)(-q+5), which can also be written as (7+q)(5-q) if you prefer it

    Hope that helped

  8. #18
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    No bio, don't tell me i'm wrong as I never put 5m, so get your facts straight. I did this in class the week before half term, and got a's for it therefore I know for sure I am right in my answers. In factorising you need brackets in your answer.
    *Signature Removed*

    Edited by opensourcehost (Forum Super Moderator): Please in future please remove signature images if the exceed the maximum size for your user group or when removal is when requested.

  9. #19
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    Quote Originally Posted by Throne Sofa
    No bio, don't tell me i'm wrong as I never put 5m, so get your facts straight. I did this in class the week before half term, and got a's for it therefore I know for sure I am right in my answers. In factorising you need brackets in your answer.
    what he meant was that if you were to multiply out your answer of m(6m+13+5), you get 6m2+13m+5m, so your answer cannot be right, as it should be 5, not 5m.

  10. #20
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    What type of Factorsing? Factorising is normaly lyke

    24p squared - 4p cubed
    P4(6p-PPP)

    ?
    Watch Scrubs on Paramount its gd

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