Higher maths Straight line Help

[BowTies1]

find the equation of the line through the point (3,5) which is parallel to the line with the equation 3x+2y -5 = 0

4) find the equation of the line through the point (2,3) prependicular to the line x-4y +7 = 0

5) P & are the points (-4,5) and (2,7)
find the equation of

(a) The line PQ
(B) The perpendicular Bisector of PQ

6. find the equation of the median Ad of traingle ABC where the coordinates of A,B and c are (-2,3) (-3,-4) and (5,2) respectively

[The Professor]

Do you want the answers or how to work them out?

[BowTies1]

a god walkthrew on how to work them out would be fine that is just like a a few out oflikie 30 ive to do so answers woudnt bother me either cause im trying more so this is jsut like examples so answers or a good walkthrew is fine

edit : i dont want JUST the answers i need to fiqure out how to do it

[kk.]

find the equation of the line through the point (3,5) which is parallel to the line with the equation 3x+2y -5 = 0

4) find the equation of the line through the point (2,3) prependicular to the line x-4y +7 = 0

5) P & are the points (-4,5) and (2,7)
find the equation of

(a) The line PQ
(B) The perpendicular Bisector of PQ

6. find the equation of the median Ad of traingle ABC where the coordinates of A,B and c are (-2,3) (-3,-4) and (5,2) respectively

4) Doesnt work. 2 - 12 + 7 doesnt = 0

equation of a line is ..... y - y1 = m (x - x1)

therefor, 5-7 / -4 - 2 = m so m = -2 / -6 --> m = 1/3

y - 7 = 1/3 (x - 2)
y = 1/3x + 7 - 2/3

y = 1/3x + 6 1/3


someone corect me if i am wrong

edit: not wrong, check with one of the points you are given

[BowTies1]

my sheet says it so it must be soemthing differnt you do

[kk.]

trust me, it doesnt work. read the edit. ill see if i can be bothered to do the other ones

[BowTies1]

ok thanks would be a great help

[kk.]

ok
5 b) center of line PQ is (-1,6) so..

m1m2 = -1 ............ m1 = 1/3

1/3 x m2 = -1
m2 = -1/.333
m2 = -3

y - y1 = m(x - x1)
y - 6 = -3 (x - -1)
y = -3 (x + 1) + 6
y = -3x -3 + 6

y = -3x + 3


substitute in (-1,6)



the last one doesnt make sense to me

[Jesus-Egg]

4) Doesnt work. 2 - 12 + 7 doesnt = 0

Read the question. (2,3) lies on the perpendicular, not on the line x - 4y + 7 = 0.

[kk.]

Read the question. (2,3) lies on the perpendicular, not on the line x - 4y + 7 = 0.

Don't correct me until u read the question. It doesn't say lies, it's the point on that line. U need the point 2,3 to work for both otherwise u can't work it out. I just finihed my AS course and I know what I'm on about