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  1. #1
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    Default Odd number squared.

    RIGHT. So, we've been set the task to prove why an odd number squared gives you an odd number. This has to be done with the use of a formula (he said something about linear and geometric formula) but I just can't get my head around it :S I googled it and everything! + Rep to anyone who can lend a hand
    Sounds like someone wants to get.... funky.

  2. #2
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    an odd number + an odd number = even therefore +another odd makes it odd again
    so like:
    3+3=6 +3=9
    5+5= 10 +5+5= 20+5 =25
    i think thats why so a formula around that

    ill take a quick think
    Last edited by dbgtz; 14-07-2010 at 08:31 PM.

  3. #3
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    n^2=2(n+p)+x

    p = previous n
    n 1-3-5--7--9
    x 1 9 25 49 81

    if you were to word it right i think thats correct.

  4. #4
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    Quote Originally Posted by Mr Selena Gomez View Post
    n^2=2(n+p)+x

    p = previous n
    n 1-3-5--7--9
    x 1 9 25 49 81

    if you were to word it right i think thats correct.
    Ah I see, but what is X?
    Sounds like someone wants to get.... funky.

  5. #5
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    you could do proof by exhaustion i spose.

    so you'd do:

    1x1 = 1
    3x3 = 9
    5x5 = 25
    7x7 = 49
    9x9 = 81

    and then say when it goes above 10, its

    11x11 = 10x1 + 10x1 + 10x10 + 1x1

    as an odd x even = even, and evenxeven = even, you only need the last to be odd. i doubt this would be the method theyre after, though

    ---------- Post added 14-07-2010 at 11:11 PM ----------

    oh, i just googled it.

    basically, an odd number can be defined as: 2k+1, where k is any constant (any integer).

    n^2, where n is the odd integer

    n = 2k+1

    = (2k+1)(2k+1)
    = 4k^2 + 4k + 1
    = 2(2k^2 + 2k) +1

    since 2k^2 + 2K is even, n^2 for n is an odd integer must be odd (due to the +1)

  6. #6
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    Essentially what kk just said.

    We can define an even number as 2n (where n is any integer) as 2 * any integer is even by definition. Therefore we can define (2n +1) as an odd number (since an even number + 1 is always odd).

    So, we square the odd number, (2n + 1)

    (2n + 1)^2 = (2n +1)(2n +1)

    = 4n^2 + 4n +1

    = 2(2n^2 +2n) + 1

    Now, the bracket (2n^2 +2n) is always going to be an integer since n is an integer. As discussed above, 2 * an integer is even by definition. Therefore 2(2n^2 +2n) must be even. When we add 1 to this we always get an odd number. Therefore an odd number squared must always be odd.
    Last edited by N!ck; 15-07-2010 at 12:49 AM.

  7. #7
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    Quote Originally Posted by crazed View Post
    Ah I see, but what is X?
    sorry i didnt word that right
    in the equation that x = the last number squared
    like i said i cant word these things right


    Also I'm pretty sure that equation isn't on this because if n=1 for it then it is
    =2(2^2 +2) + 1
    =8+4+1
    =13
    which doesn't make much sense

  8. #8
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    Quote Originally Posted by Mr Selena Gomez View Post
    sorry i didnt word that right
    in the equation that x = the last number squared
    like i said i cant word these things right


    Also I'm pretty sure that equation isn't on this because if n=1 for it then it is
    =2(2^2 +2) + 1
    =8+4+1
    =13
    which doesn't make much sense
    All I'm going to say is you're forgetting the rules of BODMAS or BIDMAS, whichever you were taught

  9. #9
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    Ive never been taught either of then, my teacher says do it in order w/e the hell that means
    so following it (i googled it) i got the same result as i did there?

  10. #10
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    B - brackets
    O/I - indices or powers of
    D - division
    M - multiplication
    A - addition
    S - subtraction

    I can't believe you've never been taught this :S it's fundamental for gcse maths o_O

    =2(2 x 1^2 + 2x1) + 1
    =2(2x1 + 2) + 1
    =2(4) + 1
    =9

    Since the odd number is defined by n=2k + 1, where k is any integer, n=3, n^2=9 which is correct

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