I need someone good at maths!

[lRhyss]

Okay so, I need some values that will for the following problem:

A, B and C are all sides of a triangle

if A, B & C are greater then 0 then they are all invalid sides for a triangle

if A = B + C or B = C + A or C = A + B then the shape is not a triangle

NOW another variable comes in; D which is always equal to 0

so D = 0

and if A is equal to B; D = D + 1
and if B is equal to C; D = D + 1
and if C is equal to A; D = D + 1

and at the end of that, if D is still equal to 0 then the triangle is Scalene
and at the end of that, if D is equal to 1 then the triangle is Isosceles
and at the end of that, if D is equal to something that is not 1 or 0 the triangle is equilateral


I need to come up with at least 4 solutions for all 3 before tomorrow and I just can't do it, I've spent like 4 days trying

Any help/solutions will be greatly appreciated

Thread moved by Nick (Forum Super Moderator): From 'Discuss Anything' as i feel it is more suited here.

[Zak]

@Kardan; is king of math.

[-:Undertaker:-]

Kardan (how do I tag him? ) is good at Maths, if I recall correctly he's doing a Maths degree. Worth asking him.

I can't even do basic maths.

[Kardan]

I'm on it

[lRhyss]

I'm on it

I will legit pay you money if you do this for me

And be your butler for anything and everything

Thanks so much for helping!!!!!!

[Kardan]

Ok, what level Maths are you doing? This seems fairly basic, so I've got a basic answer for you.

Also, check this line is correct "if A, B & C are greater then 0 then they are all invalid sides for a triangle" - I would expect it to say less than 0, rather than greater than.

Anyways, from what I've read, do you just need to find numbers for A, B and C that give you equilateral/scalene/isosceles triangles? If so, it's straight forward

[lRhyss]

Ok, what level Maths are you doing? This seems fairly basic, so I've got a basic answer for you.

Also, check this line is correct "if A, B & C are greater then 0 then they are all invalid sides for a triangle" - I would expect it to say less than 0, rather than greater than.

Anyways, from what I've read, do you just need to find numbers for A, B and C that give you equilateral/scalene/isosceles triangles? If so, it's straight forward

I think I misread that yeah, But I'm not doing a maths degree that's the thing, It's computer science IU knowit involves maths, but I really cannot do algebra D:

[Kardan]

Ok, it's fairly basic anyway.

Assuming you want them to be greater than 0.

We can select A = B = C = 1.

A, B, C are all greater than 0, so are all valid.
A =/= B + C, likewise for B and C, so shape is a triangle.
Set D = 0.
Now A = B, so D = 0 + 1 = 1.
Now B = C, so D = 1 + 1 = 2.
Now C = A, so D = 2 + 1 = 3.

Now D =/= 0 or 1, so D is equilateral.

Is this what you need? Or do you need it in terms of x?

[lRhyss]

Ok, it's fairly basic anyway.

Assuming you want them to be greater than 0.

We can select A = B = C = 1.

A, B, C are all greater than 0, so are all valid.
A =/= B + C, likewise for B and C, so shape is a triangle.
Set D = 0.
Now A = B, so D = 0 + 1 = 1.
Now B = C, so D = 1 + 1 = 2.
Now C = A, so D = 2 + 1 = 3.

Now D =/= 0 or 1, so D is equilateral.

Is this what you need? Or do you need it in terms of x?

basically I need 3 sets of 3 different numbers for each triangle, so 3 sets of different numbers that will end up being isos, 3 sets if 3 different numbers that will end up being equilateral and 3 sets of 3 numbers that will end up being scalene... If that makes sense D; sorry to be awkward and having a lack of knowledge in the subject, but it seems what is simple for you, is tricky for me

on phone xox

[Kardan]

basically I need 3 sets of 3 different numbers for each triangle, so 3 sets of different numbers that will end up being isos, 3 sets if 3 different numbers that will end up being equilateral and 3 sets of 3 numbers that will end up being scalene... If that makes sense D; sorry to be awkward and having a lack of knowledge in the subject, but it seems what is simple for you, is tricky for me

on phone xox

Well, once you have found a set, you can find another set by multiplying all numbers in that set by the same number.

So if A = 1, B = 1, C = 1 is equilateral, that means A = 2, B = 2, C = 2 is also equilateral.

For Isosceles you will have two sides the same and one different, so A = 2, B = 2, C = 1.

For Scalene, all three will be different, but you need to make sure you can't add two of them to get the third. So A = 4, B = 2, C = 1.

Can you figure out 1 more solution for equilateral and 2 more solutions for Isosceles and Scalene now?