Helpp maths (higher) +9 rep

[Ostinato]

That kids got it +REP

Kid?

[VPSwow]

Kid?

Kid/ Adult i dno what you are

Ontopic - Well done at working it out

[Ostinato]

Kid/ Adult i dno what you are

Ontopic - Well done at working it out

Lol tar

[PTER]

um, i dont understand how k = 0 when from the picture, it clearly doesnt lol. unless that picture isnt right,

[Ostinato]

um, i dont understand how k = 0 when from the picture, it clearly doesnt lol. unless that picture isnt right,

Pmsl hmmm...

[PTER]

what i can find is

QP m = 2/3

y = 2/3x + b
7 = 2/3(-3) + b
7 = -2 + b
b = 7 + 2
b = 9

y = 2/3x + 9


QR since it is perpendicular with QP, its slope would be m = -1.5

y = -1.5x + b
7 = -1.5(-3) + b
7 = 4.5 + b
b = 2.5

y = -1.5x + 2.5

substituting the given value, 5 into the second equation, you'll have

-1.5(5) + 2.5 = k
-7.5 + 2.5 = k
k = -5


and i dont know gradients, sorry

[Jõnathan]

I'VE GOT IT

Lol right...

First of all you find the gadient of QP, which = 1/2 and as PQR is 90degrees you can state that the gradient of QR is therefore -2 (perpendicular).

You then have the gradient of the line QR and you have the point Q so you just find the equation of that line - which is y= -2x + 10.

You then substitute the point R into the equation of the line so you have:-

k = -2(5) + 10
k = -10 + 10
k = 0

Lol that can't be right - the point R isn't on 0
I think that PTER's right.

[Galaxay1]

what i can find is

QP m = 2/3

y = 2/3x + b
7 = 2/3(-3) + b
7 = -2 + b
b = 7 + 2
b = 9

y = 2/3x + 9


QR since it is perpendicular with QP, its slope would be m = -1.5

y = -1.5x + b
7 = -1.5(-3) + b
7 = 4.5 + b
b = 2.5

y = -1.5x + 2.5

substituting the given value, 5 into the second equation, you'll have

-1.5(5) + 2.5 = k
-7.5 + 2.5 = k
k = -5


and i dont know gradients, sorry

k is -5

[Ostinato]

woteva gurlfriend

[Naruto!]

woteva gurlfriend

Don't give in!!