Helpp maths (higher) +9 rep

[Galaxay1]

Question:

By using gradients find the value of K.

[VPSwow]

Wow i just done maths higher and never had a question like this or even been tought this.

[-:Undertaker:-]

You know, I have no idea why they teach us useless crap like this.

HOW will this graph help us in later life?

[Galaxay1]

Idk but i need the answer :S

[Wizzdom]

You know, I have no idea why they teach us useless crap like this.

HOW will this graph help us in later life?

To find gradients which are sometimes missing?

It was like 2 years ago since i have done this, so i cant help you as i have forgotten. Sorry!

[Ostinato]

I managed to get an answer but it is completely wrong... lol.

I got a Higher B in maths and honestly you will not get a question as difficult as this - I think it's hard due to the lack of information given.

Also - how accurate is your diagram? Is it supposed to be a right angle?

My current answer is:-

k = -9x + 29 over 4

Lol it is most likely wrong but it makes sense in the terms I have done it...

[Galaxay1]

its a right angle yeh thats why i put the little angel thing in

[VPSwow]

If it was the correct shape to the question i may be able to help, but from that i cannot tell if the triangles are scaline or equalateral ect.

[Ostinato]

I'VE GOT IT

Lol right...

First of all you find the gadient of QP, which = 1/2 and as PQR is 90degrees you can state that the gradient of QR is therefore -2 (perpendicular).

You then have the gradient of the line QR and you have the point Q so you just find the equation of that line - which is y= -2x + 10.

You then substitute the point R into the equation of the line so you have:-

k = -2(5) + 10
k = -10 + 10
k = 0

[VPSwow]

I'VE GOT IT

Lol right...

First of all you find the gadient of QP, which = 1/2 and as PQR is 90degrees you can state that the gradient of QR is therefore -2 (perpendicular).

You then have the gradient of the line QR and you have the point Q so you just find the equation of that line - which is y= -2x + 10.

You then substitute the point R into the equation of the line so you have:-

k = -2(5) + 10
k = -10 + 10
k = 0

That kids got it +REP