Quick maths question as I'm just unsure and I better nail it early

[dbgtz]

If I have something like (2rt6)(rt2 + 6), when multiplying out would I do 2*rt2 or 2rt6*rt2?

[Lights]

Well you wouldn't need to change anything inside the bracket unless you have the values for r and t

so you'd just times the brackets together

[dbgtz]

Well you wouldn't need to change anything inside the bracket unless you have the values for r and t

so you'd just times the brackets together

rt is meant to be square root sorry Probably should have made that clear

[Lights]

Use ^

(2rt^6)(rt^2 + 6)

http://www.quickmath.com

Use that pratically solve 90% of your maths questions


http://www.quickmath.com/webMathemat...rt%5E2+%2B+6)+

[dbgtz]

Use ^

(2rt^6)(rt^2 + 6)

http://www.quickmath.com

Use that pratically solve 90% of your maths questions


http://www.quickmath.com/webMathematica3/quickmath/algebra/expand/basic.jsp#v1=(2rt%5E6)(rt%5E2+%2B+6)+

does ^ not mean to the power of? I meant 2√ 6 Just thought I'd go for the symbol. But this still answers my question so thanks

[Lights]

LMAO Again, i apoligise

I read "square" and simply assumed without reading the root

this is why you should use the correct annotation!

but yeah, use that website

[Wig44.]

If I have something like (2rt6)(rt2 + 6), when multiplying out would I do 2*rt2 or 2rt6*rt2?

that one

[Chippiewill]

By the way if you want to use words sqrt is much more universally accepted or even ^1/2 for square root or ^1/3 for cube root